Given that 2 is a zero of the polynomial function $f(x)$, find the remaining zeros. \[ f(x)=x^{3}-10 x^{2}+36 x-40 \] List the remaining zeros (other than 2). (Simplify your answer. Type an exact answer, using radicals and $i$ as needed. Use a comma to separate answers as needed.)

Step 1 ：Given that 2 is a zero of the polynomial function \(f(x) = x^{3} - 10x^{2} + 36x - 40\), we can find the remaining zeros by dividing the polynomial by \((x - 2)\).

Step 2 ：The quotient polynomial is then \(x^{2} - 8x + 20\).

Step 3 ：We find the zeros of this polynomial by setting it equal to zero and solving for \(x\).

Step 4 ：Solving \(x^{2} - 8x + 20 = 0\) gives us the remaining zeros of the original polynomial.

Step 5 ：Final Answer: The remaining zeros of the polynomial function \(f(x) = x^{3} - 10x^{2} + 36x - 40\) are \(\boxed{4, 5}\).