Question 1 of 33 Solve $\sqrt{4 x+24}=x+3$. Check for extraneous solutions. A. No solution B. $x=-5$ C. $x=-5,3$ D. $x=3$

Step 1 ：Square both sides of the equation to get rid of the square root, resulting in \(4x + 24 = (x + 3)^2\).

Step 2 ：Simplify the equation to solve for x, resulting in \(x^2 - 2x - 9 = 0\).

Step 3 ：Solve the equation to find the solution, which is \(x = 3\).

Step 4 ：Substitute \(x = 3\) back into the original equation to check for extraneous solutions. The original equation holds true, so \(x = 3\) is not an extraneous solution.

Step 5 ：Final Answer: The solution to the equation \(\sqrt{4 x+24}=x+3\) is \(\boxed{x=3}\).