1. Let $f(x)=2 \sqrt{3 x+4}$. Find and simplify $f(-1), f(0), f(4), f(7)$, $f(-2), f(a), f(-1+h), f(c+h)$ if possible.

Step 1 ：Let's substitute the given values of x into the function $f(x)=2 \sqrt{3 x+4}$.

Step 2 ：For $f(-1)$, substitute $-1$ for $x$ in the function to get $f(-1) = 2 \sqrt{3(-1)+4} = 2 \sqrt{1} = 2$.

Step 3 ：For $f(0)$, substitute $0$ for $x$ in the function to get $f(0) = 2 \sqrt{3(0)+4} = 2 \sqrt{4} = 4$.

Step 4 ：For $f(4)$, substitute $4$ for $x$ in the function to get $f(4) = 2 \sqrt{3(4)+4} = 2 \sqrt{16} = 8$.

Step 5 ：For $f(7)$, substitute $7$ for $x$ in the function to get $f(7) = 2 \sqrt{3(7)+4} = 2 \sqrt{25} = 10$.

Step 6 ：For $f(-2)$, substitute $-2$ for $x$ in the function to get $f(-2) = 2 \sqrt{3(-2)+4} = 2 \sqrt{-2} = 2 \sqrt{2}i$.

Step 7 ：For $f(a)$, substitute $a$ for $x$ in the function to get $f(a) = 2 \sqrt{3a+4}$.

Step 8 ：For $f(-1+h)$, substitute $-1+h$ for $x$ in the function to get $f(-1+h) = 2 \sqrt{3(-1+h)+4} = 2 \sqrt{3h+1}$.

Step 9 ：For $f(c+h)$, substitute $c+h$ for $x$ in the function to get $f(c+h) = 2 \sqrt{3(c+h)+4} = 2 \sqrt{3c+3h+4}$.

Step 10 ：Final Answer: $f(-1) = \boxed{2}$, $f(0) = \boxed{4}$, $f(4) = \boxed{8}$, $f(7) = \boxed{10}$, $f(-2) = \boxed{2\sqrt{2}i}$, $f(a) = \boxed{2\sqrt{3a + 4}}$, $f(-1+h) = \boxed{2\sqrt{3h + 1}}$, $f(c+h) = \boxed{2\sqrt{3c + 3h + 4}}$