Step 1 :The given equation is a quadratic equation in the form of \(ax^2 + bx + c = 0\). We can solve it using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
Step 2 :Here, \(a = 20\), \(b = 3\), and \(c = -9\).
Step 3 :Substituting these values into the quadratic formula, we get:
Step 4 :\(z = \frac{-3 \pm \sqrt{3^2 - 4*20*(-9)}}{2*20}\)
Step 5 :\(z = \frac{-3 \pm \sqrt{9 + 720}}{40}\)
Step 6 :\(z = \frac{-3 \pm \sqrt{729}}{40}\)
Step 7 :\(z = \frac{-3 \pm 27}{40}\)
Step 8 :So, the solutions are:
Step 9 :\(z = \frac{-3 + 27}{40} = \frac{24}{40} = \frac{3}{5}\)
Step 10 :and
Step 11 :\(z = \frac{-3 - 27}{40} = \frac{-30}{40} = -\frac{3}{4}\)
Step 12 :Thus, the solutions to the equation are \(\boxed{\frac{3}{5}, -\frac{3}{4}}\).