Problem
Enter the value of $\sum_{n=1}^{4} n-3$ \[ \sum_{n=1}^{4} n-3=\text { Ex: } 8 \]
Solution
Step 1 ：The question is asking for the sum of the series where each term is n-3, for n from 1 to 4. This means we need to calculate \((1-3) + (2-3) + (3-3) + (4-3)\) and sum these values together.
Step 2 ：The sum of the series is -2. This is the final answer.
Step 3 ：Final Answer: \(\boxed{-2}\)
