What is the value of $y$ in the solutions of the system of equations: $3 x+$ $4 y=3$ and $2 x-4 y=12$ ? (Suggest using the Addition Method)

Step 1 ：Given the system of equations: \(3x + 4y = 3\) and \(2x - 4y = 12\)

Step 2 ：Add the two equations together to eliminate one of the variables. In this case, the \(y\) terms will cancel out, leaving us with an equation in terms of \(x\): \(5x = 15\)

Step 3 ：Solve this equation for \(x\) to get \(x = 3\)

Step 4 ：Substitute \(x = 3\) back into one of the original equations to find the value of \(y\). This gives us \(y = -\frac{3}{2}\)

Step 5 ：Final Answer: The value of \(y\) in the solutions of the system of equations is \(\boxed{-\frac{3}{2}}\)