Step 1 :The problem is asking for the total amount of water that flows from the tank between \(t=1\) and \(t=e\). This can be found by integrating the rate function \(r(t)\) from \(t=1\) to \(t=e\). The integral of a rate function over an interval gives the total amount of change over that interval. In this case, it will give the total amount of water that flows out of the tank.
Step 2 :Calculate the integral of \(r(t) = t^{2} \ln (t)\) from \(t=1\) to \(t=e\).
Step 3 :The total amount of water that flows from the tank between \(t=1\) and \(t=e\) is approximately \(\boxed{4.575}\) liters.