For the function, find the point(s) on the graph at which the tangent line is horizontal.
\[
y=x^{3}-4 x^{2}+5 x+3
\]
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The point(s) at which the tangent line is horizontal is(are) (Simplify your answer. Type an ordered pair. Use a comma to separate answers as needed.)
B. The tangent line is horizontal at all points of the graph.
C. There are no points on the graph where the tangent line is horizontal.

Step 1 ：The function given is \(y=x^{3}-4 x^{2}+5 x+3\).

Step 2 ：The tangent line to a function at a given point is horizontal if and only if the derivative of the function at that point is zero.

Step 3 ：First, we need to find the derivative of the function, which is \(y' = 3x^{2} - 8x + 5\).

Step 4 ：Next, we set the derivative equal to zero and solve for x, which gives us the x-values \(x = 1\) and \(x = \frac{5}{3}\).

Step 5 ：Finally, we substitute these x-values into the original function to find the corresponding y-values, which gives us the points \((1, 5)\) and \(\left(\frac{5}{3}, \frac{131}{27}\right)\).

Step 6 ：Thus, the points on the graph at which the tangent line is horizontal are \(\boxed{(1, 5)}\) and \(\boxed{\left(\frac{5}{3}, \frac{131}{27}\right)}\).