Step 1 :The given matrix is in reduced row echelon form. This form directly gives us the solution to the system of equations. The first row corresponds to the equation \(x_1 - 8x_3 = 5\) and the second row corresponds to the equation \(x_2 + 2x_3 = -7\). We can solve these equations directly for \(x_1\) and \(x_2\) in terms of \(x_3\).
Step 2 :From the first equation, we can express \(x_1\) in terms of \(x_3\) as \(x_1 = 8x_3 + 5\).
Step 3 :From the second equation, we can express \(x_2\) in terms of \(x_3\) as \(x_2 = -2x_3 - 7\).
Step 4 :Thus, the unique solution is \(x_{1}=8x_{3} + 5\), \(x_{2}=-2x_{3} - 7\), and \(x_{3}=x_{3}\). This corresponds to the system having infinitely many solutions. The solution is \(x_{1}=8x_{3} + 5\), \(x_{2}=-2x_{3} - 7\), and \(x_{3}=t\).
Step 5 :\(\boxed{x_{1}=8x_{3} + 5, x_{2}=-2x_{3} - 7, x_{3}=t}\) is the final answer.