Applying the quadratic formula becimal answers Use the quadratic formula to solve for $x$. \[ 2 x^{2}=-3 x+7 \] Round your answer to the nearest hundredth. If there is more than one solution, separate them with commas. \[ x= \]

Step 1 ：Given the quadratic equation \(2x^{2} + 3x - 7 = 0\), we can solve for \(x\) using the quadratic formula.

Step 2 ：The quadratic formula is given by \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a\), \(b\), and \(c\) are coefficients of the quadratic equation \(ax^2 + bx + c = 0\).

Step 3 ：In this case, \(a = 2\), \(b = 3\), and \(c = -7\).

Step 4 ：Substitute these values into the quadratic formula to find the solutions for \(x\).

Step 5 ：Calculate the discriminant \(D = b^2 - 4ac = 65\).

Step 6 ：Solve for \(x\) to get \(x1 = 1.27\) and \(x2 = -2.77\).

Step 7 ：The solutions to the equation are \(x = \boxed{1.27}\) and \(x = \boxed{-2.77}\).