A ball is dropped from a height of \( 44 \mathrm{~m} \). How much time (second unit) will pass before the ball hits the ground

Step 1 ：1. \( g = 9.81 \\mathrm{m/s^2} \)

Step 2 ：2. \( h = 44 \mathrm{~m} \)

Step 3 ：3. Use formula: \( t = \sqrt{\frac{2h}{g}} \)

Step 4 ：4. Substitute given values: \( t = \sqrt{\frac{2(44)}{9.81}} \)

Step 5 ：5. Calculate t: \( t \approx 3.0063 \textrm{ s} \)