Determine all asymptotes of the following function: \[ f(x)=\frac{-8 x^{2}-2 x+28}{6 x^{2}-10 x-56} \] (Note: The vertical asymptotes can be entered in any order.) Round your answers to two decimal places. The vertical asymptotes are $x=$ and $x=$ The horizontal asymptote is $y=$

Step 1 ：To find the vertical asymptotes of a rational function, we need to find the values of x for which the denominator is equal to zero. This is because the function is undefined at these points, and the graph of the function will approach infinity or negative infinity as x approaches these values.

Step 2 ：Set the denominator equal to zero and solve for x: \(6x^2 - 10x - 56 = 0\). The solutions are \(x = -\frac{7}{3}\) and \(x = 4\). These are the vertical asymptotes.

Step 3 ：To find the horizontal asymptote of a rational function, we need to compare the degrees of the numerator and the denominator. If the degrees are the same, the horizontal asymptote is the ratio of the leading coefficients. If the degree of the denominator is greater than the degree of the numerator, the horizontal asymptote is y = 0. If the degree of the numerator is greater than the degree of the denominator, there is no horizontal asymptote.

Step 4 ：In this case, the degrees of the numerator and the denominator are the same, so the horizontal asymptote is the ratio of the leading coefficients, which is \(-\frac{4}{3}\).

Step 5 ：Final Answer: The vertical asymptotes are \(x= \boxed{-\frac{7}{3}}\) and \(x= \boxed{4}\). The horizontal asymptote is \(y= \boxed{-\frac{4}{3}}\).