Big Ideas Math Integrated - Algebra \( 1> \) T.28 Write an equation for a parallel or perpendicular line \( 5 S H \) Line \( p \) has an equation of \( y=-\frac{5}{6} x-5 \). Line \( q \) includes the point \( (9,-4) \) and is parallel to line p. What is the equation of line \( q \) ?

Step 1 ：Step 1: Find the slope of line q. Since line q is parallel to line p, their slopes are equal. The slope of line p is -\( \frac{5}{6} \). So, the slope (m) of line q is -\( \frac{5}{6} \).

Step 2 ：Step 2: Apply the point-slope form of a linear equation, which is \( y - y_1 = m(x - x_1) \), where (\( x_1, y_1 \)) is the given point and m is the slope. Substitute the point (9, -4) and the slope -\( \frac{5}{6} \).

Step 3 ：Step 3: Solve for y. \( y - -4 = -\frac{5}{6}(x - 9) \)