Solve the system of equations by graphing: \[ \left\{\begin{array}{ll} -6 x-2 y & =20 \\ y & =-3 x-10 \end{array}\right. \] Enter your answer as a numbers. If the system is inconsistent (has no solutions), enter DNE (for "does not exist") into each box. If the system is dependent-(infinite number of solutions), enter the form of solutions into each box.) Answer: $(x, y)=$

Step 1 ：First, we rewrite the first equation in the form of \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. We get \(y = 3x + 10\).

Step 2 ：We can see that the second equation is already in the form of \(y = mx + b\), with \(m = -3\) and \(b = -10\).

Step 3 ：Since the slopes of the two lines are different, the system of equations has a unique solution. The solution is the point of intersection of the two lines.

Step 4 ：We set the two equations equal to each other to find the x-coordinate of the point of intersection: \(3x + 10 = -3x - 10\).

Step 5 ：Solving for \(x\), we get \(6x = -20\), so \(x = -20 / 6 = -10 / 3\).

Step 6 ：Substituting \(x = -10 / 3\) into the second equation, we get \(y = -3(-10 / 3) - 10 = 10 - 10 = 0\).

Step 7 ：So the solution to the system of equations is \(\boxed{(-10 / 3, 0)}\).