Step 1 :The prime factorization of 14 y^{3} is 2\cdot7\cdot y\cdot y\cdot y.
Step 2 :Hiro's factored expression is (7 y^{2})(2 y) = 14y^3.
Step 3 :Bilal's factored expression is (10 y)(4 y^{2}) = 40y^3.
Step 4 :Therefore, only Hiro factored 14 y^{3} correctly, so the answer is (A) Only Hiro.