Find the equation (in terms of $x$ ) of the line through the points $(-2,2)$ and $(3,-3)$ \[ y= \] Check Answer

Step 1 ：Given two points (-2, 2) and (3, -3), we need to find the equation of the line passing through these points.

Step 2 ：We start by finding the slope of the line using the formula (y2 - y1) / (x2 - x1). Substituting the given points into the formula, we get (-3 - 2) / (3 - (-2)) = -1.

Step 3 ：Now that we have the slope, we can use the point-slope form of a line, which is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.

Step 4 ：Substituting the slope and one of the points into the equation, we get y - 2 = -1 * (x - (-2)). Simplifying this equation, we get y = -x + 0.

Step 5 ：Thus, the equation of the line is \(\boxed{y = -x}\).