Find an equation for the line parallel to $4 y+8 x=24$ and goes through the point $(-5,-3)$. Write your answer in the form $y=m x+b$. \[ y= \] Submit Question

Step 1 ：First, we find the slope of the given line. The slope of a line in the form \(ax+by=c\) is \(-a/b\). So, the slope of the given line is \(-8/4=-2\).

Step 2 ：Since parallel lines have the same slope, the slope of the line we are looking for is also \(-2\).

Step 3 ：Next, we use the point-slope form of a line, which is \(y-y_1=m(x-x_1)\), where \((x_1, y_1)\) is a point on the line and \(m\) is the slope. We substitute \((-5,-3)\) for \((x_1, y_1)\) and \(-2\) for \(m\).

Step 4 ：Finally, we simplify the equation to the form \(y=mx+b\).

Step 5 ：\(m = -2\)

Step 6 ：\(eq = y + 3 = -2*x - 10\)

Step 7 ：\(sol = -2*x - 13\)

Step 8 ：\(\boxed{y=-2x-13}\) is the final answer.