Given $h(x)=-5 x-1$, solve for $x$ when $h(x)=-6$.

Step 1 ：We are given the function \(h(x)=-5 x-1\) and we are asked to solve for \(x\) when \(h(x)=-6\). This means we need to set \(-5 x-1=-6\) and solve for \(x\).

Step 2 ：The solution to the equation is \(x=1\). This means that when \(h(x)=-6\), \(x=1\).

Step 3 ：Final Answer: \(\boxed{1}\)