Problem

4. Which fraction has a square root between 3 and 4 ? i) 52 ii) 61 iii) $\begin{array}{r}37 \\ 4\end{array}$ iv) 79 a. iv b. ii c. iii d. $\mathrm{i}$

Solution

Step 1 :Calculate the square roots of the given numbers: \(\sqrt{52}\), \(\sqrt{61}\), \(\sqrt{\frac{37}{4}}\), and \(\sqrt{79}\).

Step 2 :Find the square roots: \(\sqrt{52} \approx 7.21\), \(\sqrt{61} \approx 7.81\), \(\sqrt{\frac{37}{4}} \approx 3.04\), and \(\sqrt{79} \approx 8.89\).

Step 3 :Check which square root lies between 3 and 4: \(\sqrt{\frac{37}{4}} \approx 3.04\) is the only one.

Step 4 :Final Answer: \(\boxed{\text{c. iii}}\)

From Solvely APP
Source: https://solvelyapp.com/problems/40912/

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