Problem
2. How many grams of \( \mathrm{NaOH} \) are in \( 500 \mathrm{~mL} \) of \( 2.25 \mathrm{M} \) solution of \( \mathrm{NaOH} \) ?
Solution
Step 1 ：1. \(n_{NaOH} = \mathrm{M} \times \mathrm{V} = 2.25M \times 500mL = 2.25 \times 0.5 L\)
Step 2 ：2. \(m_{NaOH} = n_{NaOH} \times \mathrm{Molar~mass_{NaOH}} = (2.25 \times 0.5) \times 40.00 \space g/mol\)
Step 3 ：3. \(m_{NaOH} = 45.00 \space g\)
