Solve the system using substitution. \[ \left\{\begin{array}{l} -5 x+5 y=-5 \\ -4 x+y=2 \end{array}\right. \] No solution Infinite number of solutions

Step 1 ：The system of equations is given as: \[\left\{\begin{array}{l} -5 x+5 y=-5 \\ -4 x+y=2 \end{array}\right.\]

Step 2 ：First, we solve the second equation for y to get: \(y = 4x + 2\)

Step 3 ：Next, we substitute \(y = 4x + 2\) into the first equation to get a single equation in terms of x: \(-5x + 5(4x + 2) = -5\)

Step 4 ：Solving this equation gives us the value of x: \(x = -1\)

Step 5 ：Substituting \(x = -1\) back into the second equation gives us the value of y: \(y = -2\)

Step 6 ：The solution to the system of equations is \(\boxed{x = -1}\) and \(\boxed{y = -2}\)