If $\log _{2}(6 x+4)=4$, then $x=$ You may enter the exact value or round to 4 decimal places.

Step 1 ：Convert the logarithmic equation into an exponential equation. The base of the logarithm becomes the base of the power, the right side of the equation becomes the exponent, and the argument of the logarithm becomes the result. So, the equation becomes \(2^4 = 6x + 4\).

Step 2 ：Solve for x in the equation \(2^4 = 6x + 4\).

Step 3 ：Final Answer: \(x = \boxed{2.0}\)