Write the arithmetic sequence $-2,4,10,16, \ldots$ in the standard form: \[ a_{n}= \]

Step 1 ：The standard form of an arithmetic sequence is given by \(a_n = a_1 + (n-1)d\), where \(a_1\) is the first term and \(d\) is the common difference.

Step 2 ：In this case, \(a_1 = -2\) and \(d = 4 - (-2) = 6\).

Step 3 ：We can substitute these values into the formula to get the standard form of the sequence.

Step 4 ：\(a_{n} = -2 + (n-1)6 = -2 + 6n - 6 = 6n - 8\)

Step 5 ：So, the final answer is \(a_{n} = \boxed{6n - 8}\)