Problem
Question 32 (1 point) Given $\cos \theta=-\frac{\sqrt{3}}{2}$, determine all possible values of $\theta$, if $0 \leq \theta \leq 360^{\circ}$. $\theta=150^{\circ}, \theta=210^{\circ}$ $\theta=120^{\circ}, \theta=240^{\circ}$ $\theta=240^{\circ}, \theta=300^{\circ}$ $\theta=330^{\circ}, \theta=210^{\circ}$
Solution
Step 1 ：Given \(\cos \theta=-\frac{\sqrt{3}}{2}\), determine all possible values of \(\theta\), if \(0 \leq \theta \leq 360^{\circ}\).
Step 2 ：The possible values of \(\theta\) are \(\boxed{150^{\circ}}\) and \(\boxed{210^{\circ}}\).
