Simplify. \[ \sqrt{3 x} \cdot \sqrt{2 x} \]

Step 1 ：Apply the property of square roots: \(\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}\)

Step 2 ：Simplify the expression inside the square root: \(\sqrt{(3x)(2x)} = \sqrt{6x^2}\)

Step 3 ：Since \(6x^2\) does not have any perfect square factors other than \(x^2\), simplify further: \(\sqrt{6x^2} = \sqrt{6} \cdot \sqrt{x^2} = \sqrt{6} \cdot x\)

Step 4 ：Therefore, the simplified form of \(\sqrt{3x} \cdot \sqrt{2x}\) is \(\boxed{\sqrt{6} \cdot x}\)