\[ \begin{array}{l} f(x)=x-14 \\ g(x)=3 x^{2}-6 x-10 \end{array} \] Find: $f(g(x))$

Step 1 ：Given that \(f(x) = x - 14\) and \(g(x) = 3x^2 - 6x - 10\), we substitute \(g(x)\) into \(f(x)\) to find \(f(g(x))\).

Step 2 ：So, \(f(g(x)) = f(3x^2 - 6x - 10)\).

Step 3 ：By substituting \(3x^2 - 6x - 10\) into \(f(x)\), we get \(f(g(x)) = (3x^2 - 6x - 10) - 14\).

Step 4 ：Simplify the expression to get \(f(g(x)) = 3x^2 - 6x - 24\).

Step 5 ：So, the final answer is \(\boxed{f(g(x)) = 3x^2 - 6x - 24}\).