2. Find the first five terms of the recursive sequence. Show all work. \[ a_{n}--6 a_{n-1} \text { where } a_{1}-45 \]

Step 1 ：The problem is asking for the first five terms of a recursive sequence defined by the formula \(a_{n} = 6a_{n-1}\) with the initial condition \(a_{1} = 45\).

Step 2 ：To find the first five terms, we can start with the initial condition and then use the recursive formula to find each subsequent term.

Step 3 ：Using the initial condition, we know that the first term \(a_{1} = 45\).

Step 4 ：Then, using the recursive formula, we can find the second term \(a_{2} = 6a_{1} = 6*45 = 270\).

Step 5 ：Continuing in this way, we find that the third term is \(a_{3} = 6a_{2} = 6*270 = 1620\).

Step 6 ：The fourth term is \(a_{4} = 6a_{3} = 6*1620 = 9720\).

Step 7 ：And the fifth term is \(a_{5} = 6a_{4} = 6*9720 = 58320\).

Step 8 ：So, the first five terms of the recursive sequence are \(\boxed{45, 270, 1620, 9720, 58320}\).