Step 1 :The error in Jackson's solution is in Line 2. He incorrectly applied the logarithm property \(\log a^b = b \log a\). The correct application of this property to the equation in Line 1 would result in \(3x \log 16 = (x-2) \log 64\).
Step 2 :Now, let's solve the equation correctly using Jackson's method. We will start with the equation in Line 1, apply the logarithm property correctly, and then solve for x.
Step 3 :Set up the equation: \(3x \log 16 = (x - 2) \log 64\)
Step 4 :Solve the equation for x, which gives the solution \(x = -2\)
Step 5 :Final Answer: \(\boxed{-2}\)