3. The first three terms of a sequence are given. Round to the nearest thousandth (if necessary). \[ 6,36,216, \ldots \] Find the 9 th term.

Step 1 ：The given sequence is \(6, 36, 216, \ldots\)

Step 2 ：This appears to be a geometric sequence, where each term is multiplied by a constant to get the next term.

Step 3 ：To find the 9th term, we need to find the common ratio and then use the formula for the nth term of a geometric sequence, which is \(a \times r^{(n-1)}\), where \(a\) is the first term, \(r\) is the common ratio, and \(n\) is the term number.

Step 4 ：Here, \(a = 6\), \(r = 6.0\), and \(n = 9\)

Step 5 ：Substituting these values into the formula, we get the 9th term as \(6 \times 6^{(9-1)} = 10077696.0\)

Step 6 ：Final Answer: The 9th term of the sequence is \(\boxed{10077696}\)