Problem

If a given set has 26 elements, how many of its subsets have at most three elements? There are subsets that have at most three elements.

Solution

Step 1 :We are given a set with 26 elements and we are asked to find the number of its subsets that have at most three elements.

Step 2 :The subsets of a set with 26 elements that have at most three elements are the subsets with 0 elements (the empty set), 1 element, 2 elements, and 3 elements.

Step 3 :We can calculate the number of these subsets using the combination formula, which is \(nCr = \frac{n!}{(n-r)! * r!}\), where n is the total number of elements, r is the number of elements in the subset, and '!' denotes factorial.

Step 4 :Let's calculate the number of subsets with 0, 1, 2, and 3 elements separately and then add them up.

Step 5 :The number of subsets with 0 elements is \(\binom{26}{0} = 1\).

Step 6 :The number of subsets with 1 element is \(\binom{26}{1} = 26\).

Step 7 :The number of subsets with 2 elements is \(\binom{26}{2} = 325\).

Step 8 :The number of subsets with 3 elements is \(\binom{26}{3} = 2600\).

Step 9 :Adding these up, the total number of subsets with at most three elements is \(1 + 26 + 325 + 2600 = 2952\).

Step 10 :Final Answer: The number of subsets of a set with 26 elements that have at most three elements is \(\boxed{2952}\).

From Solvely APP
Source: https://solvelyapp.com/problems/39105/

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