Step 1 :The problem is asking for the number of ways to partition the number 13 into sums of 4, 3, and 1. This is a classic problem of integer partitioning, which can be solved using dynamic programming.
Step 2 :We can create a 2D array dp[i][j] where i is the number of zingers and j is the number of types of packages. dp[i][j] will store the number of ways to partition i using j types of packages.
Step 3 :We will initialize dp[i][0] = 0 for all i > 0 and dp[0][j] = 1 for all j >= 0.
Step 4 :Then, for each i and j, we will calculate dp[i][j] as the sum of dp[i][j-1] (not using the jth type of package) and dp[i - package[j]][j] (using the jth type of package).
Step 5 :Finally, dp[13][3] will give us the number of ways to partition 13 using all types of packages.
Step 6 :\(\boxed{14}\) different ways to fill the order.