Problem

4. Julio was asked to factor the expression $2 x^{2}+12 x+18$. His solution is shown below: \[ \begin{aligned} 2 x^{2}+12 x+18 & =2\left(x^{2}+10 x+9\right) \\ & =2(x+1)(x+9) \end{aligned} \] (1 mark) a. Identify the error that Julio made. (2 marks) b. Determine the correct factorization of $2 x^{2}+12 x+18$

Solution

Step 1 :Julio made an error in the factoring of the quadratic expression inside the parentheses. He factored it as \((x+1)(x+9)\), but this is incorrect. We need to find the correct factorization of the quadratic expression.

Step 2 :First, factor out the common factor of 2 from the expression: \(2x^2 + 12x + 18 = 2(x^2 + 6x + 9)\)

Step 3 :Next, factor the quadratic expression inside the parentheses: \((x^2 + 6x + 9) = (x+3)(x+3)\)

Step 4 :Finally, substitute the correct factorization back into the expression: \(2(x^2 + 6x + 9) = 2(x+3)(x+3)\)

Step 5 :\(\boxed{2(x+3)(x+3)}\) is the correct factorization of \(2x^2 + 12x + 18\)

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Source: https://solvelyapp.com/problems/38744/

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