Problem

2. A triangle has sides \( 4,6 \sqrt{5}, 14 \). Classify the triangle by its sides. (Must show work for credit!) a. Acute triangle b. Obtuse triangle c. Right triangle d. The sides lengths cannot form a triangle

Solution

Step 1 :1. Calculate the square of each side: \(4^2 = 16\), \((6\sqrt{5})^2 = 180\), \(14^2 = 196\)

Step 2 :2. Check if the sum of the squares of the two smallest sides equals the square of the largest side: \(16 + 180 = 196\)

Step 3 :3. Conclude the triangle type: The triangle is a right triangle, because the square of the largest side is equal to the sum of the squares of the other two sides

From Solvely APP
Source: https://solvelyapp.com/problems/38636/

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