Problem

Simplify: \[ \frac{3 x^{2}+3 x-6}{6 x^{2}+18 x+12} ; x \neq-2,-1 \] A. \( \frac{1}{10} \) B. \( \frac{1}{2} \) C. \( \frac{x-1}{2(x+1)} \) D. \( \frac{2(x-1)}{x+1} \)

Solution

Step 1 :Factor out 3 from the numerator and 6 from the denominator: \(\frac{3(x^2 + x - 2)}{6(x^2 + 3x + 2)}\)

Step 2 :Cancel the common factor of 3: \(\frac{x^2 + x - 2}{2(x^2 + 3x + 2)}\)

Step 3 :Factor the numerator and denominator: \(\frac{(x - 1)(x + 2)}{2(x + 1)(x + 2)}\)

Step 4 :Cancel the common factor of (x+2): \(\frac{x - 1}{2(x+1)}\)

From Solvely APP
Source: https://solvelyapp.com/problems/38603/

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