Colynomial and Rational Functions Finding the $x$-intercept(s) and the vertex of a parabola Find the $x$-intercept(s) and the coordinates of the vertex for the parabola $y=x^{2}+2 x-24$. If there is more than one $x$-intercept, separate them with commas. \[ x \text {-intercept(s): } \] vertex: (1)

Step 1 ：Set the equation \(x^{2}+2 x-24=0\) equal to zero to find the x-intercepts.

Step 2 ：Factor the equation to get \((x-4)(x+6)=0\).

Step 3 ：Set each factor equal to zero to get the solutions \(x=4\) and \(x=-6\).

Step 4 ：Use the formula \(x=-\frac{b}{2a}\) to find the x-coordinate of the vertex, where \(a=1\) and \(b=2\). This gives \(x=-1\).

Step 5 ：Substitute \(x=-1\) into the equation of the parabola to get the y-coordinate of the vertex, which is \(-25\).

Step 6 ：\(\boxed{\text{The x-intercepts are 4 and -6, and the vertex is (-1,-25).}}\)