Step 1 :We are given that the mean weight of adult males is 188 pounds and the standard deviation is 37 pounds. We are asked to find the probability that a randomly selected adult male has a weight greater than 152 pounds.
Step 2 :To solve this, we first calculate the Z-score for a weight of 152 pounds. The Z-score is a measure of how many standard deviations an element is from the mean. It is calculated using the formula \(Z = \frac{X - \mu}{\sigma}\), where \(X\) is the value we are interested in, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.
Step 3 :Substituting the given values into the formula, we get \(Z = \frac{152 - 188}{37} = -0.972972972972973\).
Step 4 :The Z-score tells us how many standard deviations below the mean a weight of 152 pounds is. A negative Z-score indicates that the value is below the mean.
Step 5 :We then find the probability that a randomly selected adult male has a weight greater than this Z-score. This is equivalent to finding the area to the right of the Z-score on the standard normal distribution curve.
Step 6 :Using a standard normal distribution table or a calculator, we find that the probability is approximately 0.8347166325829531.
Step 7 :Rounding to four decimal places, the probability that a randomly selected adult male has a weight greater than 152 pounds is approximately 0.8347. This means that about 83.47% of adult males weigh more than 152 pounds.
Step 8 :Final Answer: The probability that 1 randomly selected adult male has a weight greater than 152 pounds is approximately \(\boxed{0.8347}\).