Step 1 :The function is in the form of \(\frac{0}{0}\) when \(x=3\). This is an indeterminate form, so we can't directly substitute \(x=3\) into the function to find the limit.
Step 2 :However, we can simplify the function by factoring the numerator and the denominator. The function \(\frac{2 x^{2}+6 x-36}{x^{2}-9}\) simplifies to \(\frac{2(x + 6)}{x + 3}\).
Step 3 :After simplifying, we can substitute \(x=3\) into the simplified function to find the limit.
Step 4 :The limit of the function as \(x\) approaches 3 is \(\boxed{3}\).