Problem

The following statistics represent weekly salaries at a construction company. $\begin{array}{llll}\text { Mean } & \$ 465 & \text { First quartile } & \$ 400 \\ \text { Median } & \$ 475 & \text { Third quartile } & \$ 550 \\ \text { Mode } & \$ 535 & 85 \text { th percentile } & \$ 703\end{array}$ The most common salary is $\$ 535$. The salary that half the employees' salaries surpass is $\$ 475$. The percent of employees' salaries that surpassed $\$ 50$ is . \%.

Solution

Step 1 :From the given statistics, we know that the most common salary is $535, which is the mode.

Step 2 :The salary that half the employees' salaries surpass is $475, which is the median.

Step 3 :We are asked to find the percent of employees' salaries that surpassed $50.

Step 4 :Since all the given salaries are greater than $50, we can conclude that 100% of the employees' salaries surpassed $50.

Step 5 :So, the answer is \(\boxed{100}\) percent.

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Source: https://solvelyapp.com/problems/37184/

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