Let $f(x, y)=2^{x}+8 x y$, find $f(0,-3), f(-3,2)$, and $f(3,2)$. $f(0,-3)=\square$ (Simplify your answer. $)$

Step 1 ：Let's substitute $x=0$ and $y=-3$ into the function $f(x, y)=2^{x}+8 x y$.

Step 2 ：After substituting, we get $f(0,-3)=2^{0}+8*0*(-3)$.

Step 3 ：Simplifying the expression, we get $f(0,-3)=1+0$.

Step 4 ：So, $f(0,-3)=1$.

Step 5 ：Final Answer: \(\boxed{1}\)