Problem
Suppose that the function $h$ is defined on the interval $(-2,2]$ as follows.
\[
h(x)=\left\{\begin{array}{ll}
-1 & \text { if }-2
Solution
Step 1 ：The function h(x) is defined piecewise, meaning it has different definitions for different intervals of x.
Step 2 ：To find h(-1), h(0.5), and h(2), we need to determine which interval each of these values falls into, and then apply the corresponding definition.
Step 3 ：For h(-1), -1 falls into the interval -2
Step 4 ：For h(0.5), 0.5 falls into the interval 0
Step 5 ：For h(2), 2 falls into the interval 1
Step 6 ：\(\boxed{h(-1) = -1, h(0.5) = 1, h(2) = 2}\)
From Solvely APP
Solution
Step 1 ：The function h(x) is defined piecewise, meaning it has different definitions for different intervals of x.
Step 2 ：To find h(-1), h(0.5), and h(2), we need to determine which interval each of these values falls into, and then apply the corresponding definition.
Step 3 ：For h(-1), -1 falls into the interval -2 Step 4 ：For h(0.5), 0.5 falls into the interval 0 Step 5 ：For h(2), 2 falls into the interval 1 Step 6 ：\(\boxed{h(-1) = -1, h(0.5) = 1, h(2) = 2}\)
