Step 1 :Given the demand functions for coffee from professionals and students as \(q_{P}=700-100 P_{P}\) and \(q_{S}=200-40 P_{S}\) respectively, where \(q_{P}\) is the number of coffee drinks demanded by professionals and \(q_{S}\) is the number of coffee drinks demanded by students. \(P_{P}\) is the price of a coffee drink for a professional, and \(P_{S}\) is the price of a coffee drink for a student.
Step 2 :Solving the demand functions for the price, \(P\), as a function of the quantity demanded, \(q\), gives the two inverse demand functions for coffee for these two groups: \(P_{P}=7-0.01 q_{P}\) and \(P_{S}=5-0.025 q_{S}\).
Step 3 :The cost of selling \(Q\) coffee drinks is given by the function \(T C(Q)=2 Q+100\).
Step 4 :To find the profit-maximizing quantity of coffee drinks Kosty Koffie will sell to professionals, we need to set up the profit function for professionals and then find the quantity that maximizes this function.
Step 5 :The profit function is given by the difference between total revenue and total cost. Total revenue is the price per coffee drink times the quantity of coffee drinks sold, and total cost is given by the cost function.
Step 6 :We can substitute the inverse demand function for the price in the total revenue to express it as a function of quantity. Then we can take the derivative of the profit function with respect to quantity and set it equal to zero to find the quantity that maximizes profit.
Step 7 :Setting up the profit function for professionals: \(profit_P = q_P*(7 - 0.01*q_P) - 2*q_P - 100\).
Step 8 :Taking the derivative of the profit function with respect to quantity: \(profit_P_derivative = 5 - 0.02*q_P\).
Step 9 :Setting the derivative equal to zero and solving for \(q_P\) gives the profit-maximizing quantity of coffee drinks Kosty Koffie will sell to professionals.
Step 10 :Final Answer: The profit-maximizing quantity of coffee drinks Kosty Koffie will sell to professionals is \(\boxed{250}\).