A company makes two types of biscuits: Jumbo and Regular. The oven can cook at most 300 biscuits per day. Each jumbo biscuit requires $2 \mathrm{oz}$ of flour, each regular biscuit requires $1 \mathrm{oz}$ of flour, and there is 400 oz of flour available. The income from each jumbo biscuit is $\$ 0.11$ and from each regular biscuit is $\$ 0.07$. How many of each size biscuit should be made to maximize income? What is the maximum income? The company should make jumbo and regular biscuits. The maximum income is $\$$

Step 1 ：This is a linear programming problem. We have two variables, the number of jumbo biscuits (J) and the number of regular biscuits (R). We have two constraints: the total number of biscuits cannot exceed 300, and the total amount of flour used cannot exceed 400 oz. We want to maximize the income, which is \(0.11J + 0.07R\).

Step 2 ：The feasible region is a polygon in the first quadrant, bounded by the lines \(J+R=300\), \(2J+R=400\), \(J=0\), and \(R=0\). The income is maximized at a vertex of this polygon.

Step 3 ：We can find the vertices by solving the system of linear equations formed by each pair of lines. Then we can calculate the income at each vertex and choose the one that gives the maximum income.

Step 4 ：The solution to the system of equations is \(J=100\) and \(R=200\). This means that the company should make 100 jumbo biscuits and 200 regular biscuits. The income at this point is $25.00.

Step 5 ：We also need to check the income at the other vertices of the feasible region, which are \((0,300)\), \((0,400)\), and \((300,0)\).

Step 6 ：The income at \((0,300)\) is $21.00, at \((0,400)\) is $28.00, and at \((300,0)\) is $33.00.

Step 7 ：The maximum income is obtained when the company makes 300 jumbo biscuits and no regular biscuits. The maximum income is \(\boxed{33.00}\).