Problem

Find the angle, \( \alpha \), between the vectors. \[ \begin{array}{l} \overrightarrow{\mathrm{u}}=\langle-2,3\rangle \\ \overrightarrow{\mathrm{w}}=\langle 4,-2\rangle \end{array} \]

Solution

Step 1 :\(\cos\alpha = \frac{\overrightarrow{u} \cdot \overrightarrow{w}}{||\overrightarrow{u}|| ||\overrightarrow{w}||}\)

Step 2 :\(\cos\alpha = \frac{(-2)(4) + (3)(-2)}{\sqrt{(-2)^2 + 3^2} \sqrt{4^2 + (-2)^2}}\)

Step 3 :\(\alpha =\cos^{-1}\left(\frac{-14}{\sqrt{13}\sqrt{20}}\right)\)

From Solvely APP
Source: https://solvelyapp.com/problems/34603/

Get free Solvely APP to solve your own problems!

solvely Solvely
Download