Problem

Find the values of \( x \) and \( y \) in parallelogram PQRS. \[ \text { PT }=y, T R=4 x+1, Q T=2 y, T S=3 x+12 \]

Solution

Step 1 :PT = TS \Rightarrow y = 3x + 12

Step 2 :TR = QT \Rightarrow 4x + 1 = 2y

Step 3 :Substitute: 4x + 1 = 2(3x + 12)

Step 4 :Solve: x = -7, y = 9

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Source: https://solvelyapp.com/problems/34581/

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