Problem

Find the volume of the solid generated by revolving the region bounded by the graphs of \( y=0, x=2 \), and \( y=x^{2} \) about the line \( y=-1 \)

Solution

Step 1 :Set up the washer method for volume: \( V = \pi \int_{a}^{b} (R^{2}(x) - r^{2}(x)) dx \)

Step 2 :Calculate the outer radius R(x) and inner radius r(x) based on the functions and line of revolution

Step 3 :Evaluate the integral and find the volume: \( V = \pi \int_{0}^{2} (1 - (x^{2} + 1)^{2}) dx \)

From Solvely APP
Source: https://solvelyapp.com/problems/34445/

Get free Solvely APP to solve your own problems!

solvely Solvely
Download