What is the range of the given exponential function below? \[ 2^{x}-1 \]

Step 1 ：The given function is \(2^{x}-1\).

Step 2 ：The range of an exponential function of the form \(f(x) = a^x\) where \(a > 0\) and \(a \neq 1\) is \((-\infty, \infty)\).

Step 3 ：However, in this case, the function is shifted down by 1 unit.

Step 4 ：So the range should be \((1 - 1, \infty) = (0, \infty)\).

Step 5 ：Final Answer: The range of the given exponential function is \(\boxed{(0, \infty)}\).