Use the explicit formula $a_{n}=a_{1}+(n-1) \cdot d$ to find the 250th term of the sequence below. \[ 57,66,75,84,93, \ldots \] A. 2241 B. 2307 C. 2334 D. 2298

Step 1 ：The given sequence is an arithmetic sequence. In an arithmetic sequence, the difference between any two successive terms is constant. This constant difference is called the common difference (d). The explicit formula for an arithmetic sequence is given by \(a_{n}=a_{1}+(n-1) \cdot d\), where \(a_{n}\) is the nth term, \(a_{1}\) is the first term, and n is the term number.

Step 2 ：From the given sequence, we can observe that the common difference (d) is 9 (66-57 = 9, 75-66 = 9, etc.). The first term (\(a_{1}\)) is 57. We are asked to find the 250th term (\(a_{250}\)), so n = 250.

Step 3 ：We can substitute these values into the explicit formula to find the 250th term.

Step 4 ：\(a_{1} = 57\)

Step 5 ：d = 9

Step 6 ：n = 250

Step 7 ：\(a_{n} = 2298\)

Step 8 ：Final Answer: The 250th term of the sequence is \(\boxed{2298}\)