Problem

Question 3 of 10 What is the recursive formula for this sequence? $14,18,22,26,30, \ldots$ A. $\left\{\begin{array}{l}a_{1}=4 \\ a_{n}=a_{n-1}+14\end{array}\right.$ B. $\left\{\begin{array}{l}a_{1}=14 \\ a_{n}=a_{n-1}-4\end{array}\right.$ C. $\left\{\begin{array}{l}a_{1}=34 \\ a_{n}=a_{n-1}+4\end{array}\right.$ D. $\left\{\begin{array}{l}a_{1}=14 \\ a_{n}=a_{n-1}+4\end{array}\right.$

Solution

Step 1 :The problem is asking for the recursive formula for the sequence $14,18,22,26,30, \ldots$

Step 2 :The first term of the sequence is 14, and each subsequent term is 4 more than the previous term.

Step 3 :This matches with option D. So, the recursive formula for this sequence is $a_{1}=14$ and $a_{n}=a_{n-1}+4$.

Step 4 :Checking the first 6 terms of the sequence, which are [14, 18, 22, 26, 30, 34]. These match the given sequence, so the recursive formula is correct.

Step 5 :Final Answer: The recursive formula for this sequence is \(\boxed{\left\{\begin{array}{l}a_{1}=14 \\ a_{n}=a_{n-1}+4\end{array}\right.}\) (Option D).

From Solvely APP
Source: https://solvelyapp.com/problems/33654/

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