The container that holds the water for the football team is $\frac{1}{2}$ full. After pouring in 6 gallons of water, it is $\frac{7}{10}$ full. How many gallons can the container hold? Џillons

Step 1 ：The problem is asking for the total capacity of the container. We know that the difference between \(\frac{7}{10}\) and \(\frac{1}{2}\) of the container's capacity is 6 gallons. We can set up an equation to solve for the total capacity of the container.

Step 2 ：Let's denote the total capacity of the container as C. The difference between \(\frac{7}{10}\)C and \(\frac{1}{2}\)C is 6 gallons. Therefore, we can write the equation as \(\frac{7}{10}\)C - \(\frac{1}{2}\)C = 6.

Step 3 ：Solving this equation, we find that C is approximately 30 gallons.

Step 4 ：Final Answer: The container can hold approximately \(\boxed{30}\) gallons.