Problem

11. The owner of a grocery store had an income of $\$ 6,145$ and operating costs of $\$ 3,920$ for a given time period. What percent of the store's income was profit? Round to the nearest tenth of a percent. $56.8 \%$ $36.2 \%$ $63.8 \%$ $42.7 \%$

Solution

Step 1 :Given that the income of the grocery store is \$6145 and the operating costs are \$3920.

Step 2 :The profit is calculated as the difference between the income and the operating costs, which is \$6145 - \$3920 = \$2225.

Step 3 :To find the percentage of the income that was profit, we divide the profit by the income and multiply by 100, which is \(\frac{2225}{6145} \times 100\approx 36.208299430431246\%\).

Step 4 :Rounding to the nearest tenth of a percent, we get approximately 36.2\%.

Step 5 :Final Answer: The profit was approximately \(\boxed{36.2 \%}\) of the store's income.

From Solvely APP
Source: https://solvelyapp.com/problems/32250/

Get free Solvely APP to solve your own problems!

solvely Solvely
Download